来源:Leetcode
原帖:http://oj.leetcode.com/problems/merge-sorted-array/
题目:
Given two sorted integer arrays A and B, merge B into A as one sorted array. You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively.
Solution: From back to forth.
代码:
原帖:http://oj.leetcode.com/problems/merge-sorted-array/
题目:
Given two sorted integer arrays A and B, merge B into A as one sorted array. You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively.
Solution: From back to forth.
代码:
class Solution {
public:
void merge(int A[], int m, int B[], int n) {
int i = m - 1;
int j = n - 1;
int x = m + n - 1;
while (i >= 0 && j >= 0) {
if (A[i] >= B[j]) {
A[x--] = A[i--];
} else {
A[x--] = B[j--];
}
}
while (j >= 0) { // B is longer than A
A[x--] = B[j--];
}
}
};
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