来源:Leetcode
原帖:https://oj.leetcode.com/problems/distinct-subsequences/
题目:
Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is a subsequence of "ABCDE" while "AEC" is not).
Here is an example:
S = "rabbbit", T = "rabbit"
Return 3.
代码:
原帖:https://oj.leetcode.com/problems/distinct-subsequences/
题目:
Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is a subsequence of "ABCDE" while "AEC" is not).
Here is an example:
S = "rabbbit", T = "rabbit"
Return 3.
代码:
class Solution {
public:
//dp. T[i] 前i个字符 与 S[j] 前j个字符的匹配
int numDistinct(string S, string T) {
int N = S.size(), M = T.size();
int dp[M + 1][N + 1];
for (int j = 0; j <= N; ++j) {
dp[0][j] = 1; // starting with 0
}
for (int i = 1; i <= M; ++i) {
dp[i][0] = 0; // starting with 1
}
for (int i = 1; i <= M; ++i) { // size of T
for (int j = 1; j <= N; ++j) {// size of S
if (S[j - 1] == T[i - 1]) {
dp[i][j] = dp[i][j - 1] + dp[i - 1][j - 1];
} else {
dp[i][j] = dp[i][j - 1];
}
}
}
return dp[M][N];
}
};
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